2x^-3y^2/3x^-3y^3*3x^0

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Solution for 2x^-3y^2/3x^-3y^3*3x^0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x^0*x^-3*((2*x^-3*y^2)/3)*y^3 = 0

3*x^-3*((2*x^-3*y^2)/3)*y^3 = 0

2*x^-6*y^5 = 0 // : 2*y^5

x^-6 = 0

x należy do O

x belongs to the empty set

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